If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2-10x-90=0
a = 9; b = -10; c = -90;
Δ = b2-4ac
Δ = -102-4·9·(-90)
Δ = 3340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3340}=\sqrt{4*835}=\sqrt{4}*\sqrt{835}=2\sqrt{835}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{835}}{2*9}=\frac{10-2\sqrt{835}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{835}}{2*9}=\frac{10+2\sqrt{835}}{18} $
| -10+6w=-2w+3(-1w+4) | | 2x+(x+27)=180 | | 18-9m=-3(m+6) | | 4-2x=39-9x+2x | | 5x+20°=2x+12° | | (4x-5)°=80° | | y″+100y=0 | | 5(3b+7)‐1/3b=20 | | 4x+-5=6x+-1 | | 2.5x-1.6=5.9 | | k=50,3.6 | | -3x-4(x-4)=58 | | x=-13x+1 | | 90=-6(3a+3) | | -33=3(xx-9) | | 5/2x+1=26 | | -33=(3x-9) | | 11+0x-7=6 | | 80+10x=20x | | y=70+350 | | 7(3+5y)=5(4-y) | | 7(3+5y)=5(4-y | | 1/4y+5=1/10y. | | 14y+5=110y. | | 3(2y+11=4(4y+2) | | 19=2x-(-13) | | 5x+82=x2-3x+18 | | -79=7w+34w-1 | | 7x+3-3x=11 | | y-4=3(y-2) | | －5(6+6n)=－n－30 | | 2^x3^x=1296 |